Allie got three suitcases that needs to be checked-in. The airlines allow not more than 30 kg as check-in bags. The first suitcase can carry 2 kg more than half of the second suitcase and the third suitcase can carry 3 times the sum of the other two suitcases. What is the biggest number that any of the three suitcases can carry?
Answers
Answer:
Step-by-step explanation:
if total weight allie carries is 30 kgs (max weight allowed)
let the second suitcase carry x kgs
∵the total weight that can be carried = 30
x cannot be > than 30
now given
the first bag can carry x/2 kg+2 kg
the third suitcase can carry
(x/2+ 2+x)(3)kg =3x/2+6+x kg
∴x+x/2 kg+2 kg+3x/2+6+x kg=30
=8x/2kg+8kg=30
=>8x/2=22
=>8x=44
=>x=5.5
if total weight allie carries is 30 kgs (max weight allowed)
let the second suitcase carry x kgs
∵the total weight that can be carried = 30
x cannot be > than 30
now given
the first bag can carry x/2 kg+2 kg
the third suitcase can carry
(x/2+ 2+x)(3)kg =3x/2+6+x kg
∴x+x/2 kg+2 kg+3x/2+6+x kg=30
=8x/2kg+8kg=30
=>8x/2=22
=>8x=44
=>x=5.5
if total weight allie carries is 30 kgs (max weight allowed)
let the second suitcase carry x kgs
∵the total weight that can be carried = 30
x cannot be > than 30
now given
the first bag can carry x/2 kg+2 kg
the third suitcase can carry
(x/2+ 2+x)(3)kg =3x/2+6+x kg
∴x+x/2 kg+2 kg+3x/2+6+x kg=30
=8x/2kg+8kg=30
=>8x/2=22
=>8x=44
=>x=5.5(secoend suitcase)
x/2+2=4.75(first suitcase)
(x/2+ 2+x)(3)=10.25