Question

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calculate the number of molecules and number of atoms present in 11.2 litres of oxygen ( O2 ) at normal temperature and pressure.

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Answer 1

At NTP, 1 mol of any gas will have a volume of 22.4 litre.
22.4 l=>1 mol
11.2 l=>1*11.2/22.4=0.5 mol
So there is 0.5 mol O2 present.
0.5 mol O2 will contain 6.022*10^23*0.5 molecules = 3.011*10^23 molecules.
1 mol O2 contains 2 mol atoms, so 0.5 mol O2 will contain 1 mol atoms=6.022*10^23 atoms.