alok's age is four times his son's age. eight years ago, he was twelve times his son's age. find their present ages.
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Answered by
22
Let his son be x now
Alok will be 4x now
8 years ago,
His son = x - 8
Alok = 4x - 8
8 years go, Alok is 12 times his son's age:
4x - 8 = 12(x - 8)
Solve for x:
4x - 8 = 12(x - 8)
4x - 8 = 12x - 96
12x - 4x = 96 - 8
8x = 88
x = 11
His son = x = 11 years old
Alok = 4x = 11 x 4 = 44 years old
Answer: Alok is 44 years old and his son is 11 years old
Answered by
6
Let the son's age be ( x ) years
So, alok's age will be ( 4x ) Years
8 years back, he was twelve time of his son's age
ATQ,
=> ( 4x - 8 ) = 12( x - 8 )
=> 4x - 8 = 12x - 96
=> 96 - 8 = 12x - 4x
=> 88 = 8x
=> 11 = x
Hence, Present age of alok's son = x = 11 years
And present age of alok = 4(11)= 44 years
So, alok's age will be ( 4x ) Years
8 years back, he was twelve time of his son's age
ATQ,
=> ( 4x - 8 ) = 12( x - 8 )
=> 4x - 8 = 12x - 96
=> 96 - 8 = 12x - 4x
=> 88 = 8x
=> 11 = x
Hence, Present age of alok's son = x = 11 years
And present age of alok = 4(11)= 44 years
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