Question

Alok started to move in the direction of East and
turned to his left after moving 25 m. Then he turned
to his left after moving 10 m and after this he moved
35 m. Then he turned to his left and moved 20
m. Now how far is he from his starting point?​

Answer 1

Answer:

14m is the correct answer

Answer 2

The distance of Alok from his starting point is $10\sqrt{2}$ m.

Given,

Alok started to move towards the East,

turns left after moving 25 m,

again turns left after moving 10 m, and moves 35 m.

Again turns left and moves 20 m.

To find,

How far is he from his starting point?

Solution,

Refer figure.

Let Alok starts from point A.

From the figure, we can observe that the path followed by Alok is

A - P - Q - R - S.

The final position of Alok is S.

We can see that how far is he from starting point (SA), can be determined by applying Pythagoras theorem in ΔAMS since it is a right triangle.

So,

$SA^2=AM^2+MS^2 \hfill ...(1)$

Here,

AM = PM - PA = 35 - 25 = 10 m,

MS = RS - RM = 20 - 10 = 10 m.

Substituting the above values in (1), we get,

$SA^2=10^2+10^2$

$\implies SA=\sqrt{100+100}$

$\implies SA=10\sqrt{2}$ m.

Therefore, the distance of Alok from his starting point is $10\sqrt{2}$ m.

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