Math, asked by Humaira21, 11 months ago

Find x such that(3/5)^3 × (3/5)^-6 = (3/5)^2x-1​

Answers

Answered by Gautam7448
0

Answer:

base same h to power ko equate kar do

easily u will get the answer

Answered by warylucknow
4

Answer:

The value of x is -1.

Step-by-step explanation:

Exponents rule:

  • a^{m}\times a^{n}=a^{m+n}\\
  • If a^{m}=a^{n} then m = n.

Solve for x as follows:

(\frac{3}{5})^{3}\times(\frac{3}{5})^{-6}=(\frac{3}{5})^{2x-1}\\(\frac{3}{5})^{3-6}=(\frac{3}{5})^{2x-1}\\(\frac{3}{5})^{-3}=(\frac{3}{5})^{2x-1}\\-3=2x-1\\2x=-2\\x=-1

Thus, the value of x is -1.

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