Question

alpha and bita are zeroes of the polynomial x^2 - 6x +y . find the value of of y if 3(alpha) + 2(bita) = 20.

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Answer 1

x^2 - 6x+y = 0

alpha and beta are the zeroes of polynomial

$\alpha + \beta = 6 \\ \alpha \beta = y$

given

$3 \alpha + 2 \beta = 20$

solving these equations .we get

$\alpha = 8 \\ \beta = - 2$

putting these values in equation.

(8)(-2)=y

y= -16

Answer 2

Refer to the attachment

Answer wasn't able to be posted that way saying it that I used rude words.

Thank yOu!