Question

alpha ,beta,gamma are the zeroes of the 2x^3-4x^2+5x+6,find the value of
1.alpha+beta+gamma
2.alpha beta+beta gamma+gamma alpha
3.alpha beta gamma

Answer 1

Given polynomial a=2 b=-4 c=5 d=6 Alfa +bita +gama = -b/a=4/2=2 Alfa×bita+bita×gama+gama×alpha=c/a=5/2 Alfa×bita×gama=-d/a=-6/2=-3