Question

\alpha . \beta . \gamma .are \the \: zeroes \: of \: the \: cubic \: polynomial \: p(x) = x3 - 2x ^{2} + qx - r. \: if \alpha + \beta = 0. \: then \: \: that \: 2q = r \\ ​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

α+β+γ = -b/a = -(-2)/1 = 2

if α+β = 0

0+γ = 2

next step:

αβ + βγ + γα = c/a = q/1 = q

if we expand it , it will be

αβ + γ(α+β) = q

αβ+ γ(0)= q

αβ = q

next step:

αβγ = -d/a

= -(-r)/1

= r

q × γ = r

q × 2 = r

2q = r