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Or,
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4
Answer:
-c/b will be answer
Step-by-step explanation:
=> 1/@ + 1/ß
=> @ß/ @+ß. ------(1)
so, now we know that
=> @ß = c/a. and. @ + ß = - b/a
put in (1)
=> c/a upon -b/a
=> -c/b
hope this will help uhh
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