Question

alpha3+beta3, if alpha+beta are zeros of 3x3+5x+13

Answer 1

Answer:

Let alpha and beta be m and n

m + n = 5/3

mn = 2/3

alpha^3 + beta^3

= m^3 + n^3

= (m+n)^3 - 3mn ( m+n )

= (5/3)^3 - 3×(2/3) (5/3)

= ( 125/27) - (10/3)

= ( 125 - 90 ) /27

= 35 / 27