Chemistry, asked by anujjaiswal7697, 10 months ago

Although the H-bonding in hydrogen fluoride is much stronger than that in water, yet water has a much higher boiling point than hydrogen fluoride. Why? [Foreign 2012]

Answers

Answered by Anonymous
2

Answer:

In a molecule of water, there are two hydrogen bond donors, while a hydrogen fluoride molecule only has one donor. There is only one donor in HF, but there are 2 hydrogen atoms in H

2

O. The oxygen molecule in water has two lone pairs which are capable of accepting two hydrogen bonds. Therefore, a single water molecule can have up to 4 hydrogen bonds, i.e., 1 for each hydrogen and 2 for the oxygen. On the other hand, HF can only undergo 2 hydrogen bonds per molecule.

Answered by Pikachu07
1

Answer:

In a molecule of water, there are two hydrogen bond donors, while a hydrogen fluoride molecule only has one donor. There is only one donor in HF, but there are 2 hydrogen atoms in H

2

O. The oxygen molecule in water has two lone pairs which are capable of accepting two hydrogen bonds. Therefore, a single water molecule can have up to 4 hydrogen bonds, i.e., 1 for each hydrogen and 2 for the oxygen. On the other hand, HF can only undergo 2 hydrogen bonds per molecule.

Hence, it is clear that water has more hydrogen bonds per molecule and per molecular mass as compared to HF which allows water to form a complex network of hydrogen bonding that creates a high surface tension and consequently a higher boiling point than HF.

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