altitude BD and CE are equal show that triangle ABC is an isosceles triangle
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channa21:
congruent (RHS) SO AE=AD and EB=DC adding both we get AB=AC hence Isosceles triangle
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In ∆ABD &∆AEC
/_A=/_A(common)
/_ADB=/_AEC(90° EACH)
BD=CE(given)
∆ABD≈∆AEC( by AAS criteria)
AB=AC
So ∆ABC is an isosceles triangle
/_A=/_A(common)
/_ADB=/_AEC(90° EACH)
BD=CE(given)
∆ABD≈∆AEC( by AAS criteria)
AB=AC
So ∆ABC is an isosceles triangle
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