altitude of a triangle is 5 cm less than its base area of triangle is 15 cm² find its base and its altitude
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Answer:
let base be=x
therefore altitude=x5
area of the triangle=1/2 *base*altitude
=1/2*x*x-5
ATQ
1/2*x*x-5=15
x*x-5=15*2
x²-5=30
x²=30+5
x²=35
x=√35
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