Question

Aluminum reacts with chlorine to form aluminum chloride. The equation for this
reaction is 2 Al(s) + 3 Cl2(g) 2 AlCl3(s). What is the percentage yield for a reaction in which 33.5 g of aluminum is reacted with excess chlorine to produce 164.5 g of aluminum chloride? Use the molar mass values given here.
= 26.9815 g/mol
= 70.9064 g/mol
= 133.3411 g/mol
options:
a) 66.8%
b) 99.4%
c) 100.6%
d) 49.7%

Answer 1

Answer:

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Explanation:

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