Am A.P consists of 50 terms of which 3rd term is 12 and the last term is 106.Find the 29th term.
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a+2d=12
a+49d=106
By Elimination Method,
47d=94
d=94/47=2
substitute value of d in any equation,
a+2*2=12
a=12-4=8
a+28d=29th term
8+28*2=8+56=64
therefore,a·29=64
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