AM is a median of a ∆ABC.
Prove that AB+BC+CA>2AM
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Answer:We know,
In a triangle sum of two sides is greater than the third side
Hence ,In triangle ABM
AB + BM > AM
Also in triangle ACM
AC + MC > AM
Adding equation 1 and 2 we get,
AB + BM + AC + MC > AM + AM
AB + AC + (BM + MC) > 2AM
AB + AC + BC > 2AM
Step-by-step explanation:please mark me as brainliest
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