Math, asked by sarojinid791, 2 months ago

AM is a median of a ∆ABC.
Prove that AB+BC+CA>2AM​

Attachments:

Answers

Answered by pushpalathamouneshpu
6

Answer:We know,

In a triangle sum of two sides is greater than the third side

Hence ,In triangle ABM  

AB + BM > AM  

Also in triangle ACM

AC + MC > AM  

Adding equation 1 and 2 we get,

AB + BM + AC + MC  > AM + AM

AB + AC + (BM + MC) > 2AM

AB + AC + BC > 2AM

Step-by-step explanation:please mark me as brainliest

Similar questions