Question

AM is a median of a triangle ABC. IS AB + BC + CA > 2AM ? ( Consider the sides of triangles ∆ ABM and ∆ AMC )

Please can u make it fast

Answer 1

Answer:

Yes, given expression is true.

Step-by-step explanation:

Consider the triangle ABM.

Here, AB + BM > AM --- 1 (sum of two sides greater than third)

Consider the triangle AMC.

Here, CM + AC > AM --- 2 (sum of two sides greater than third)

Adding eqn 1 and 2, we get -

AB + BM + CM + AC > 2AM

AB + (BM+CM) + AC > 2AM

AB + BC + AC > 2AM.

Thus, given statement is true.

Answer 2

Answer:

I think it's clear

Step-by-step explanation:

and we got BC in the 6 th step by

( BM+CM)

M is the common so we got BM