Math, asked by pahle, 11 hours ago

am is a median of a triangle abc. is ab + bc + ca > 2am. how?

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Answered by Nuceo
2

Answer:

Yes

Step-by-step explanation:

In ΔAMB

AB + BM > AM (Sum of sides of a triangle is always greater than or equal to third side) ---- 1

Similarly, AC + CM > AM ---- 2

Adding 1 and 2

AB + AC + ( BM + CM ) > 2AM

AB + AC + BC > 2AM

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Answered by ItzZzArry
2

Answer:

So, in the triangle ABC. We have sub triangles ABM and AMC. Using the inequality of the triangle that the sum of any two sides is always greater than or equal to the third side. Hence AB+BC+CA>2AM is proved to be true

Step-by-step explanation:

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