am is a median of a triangle abc. is ab + bc + ca > 2am. how?
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Answer:
Yes
Step-by-step explanation:
In ΔAMB
AB + BM > AM (Sum of sides of a triangle is always greater than or equal to third side) ---- 1
Similarly, AC + CM > AM ---- 2
Adding 1 and 2
AB + AC + ( BM + CM ) > 2AM
AB + AC + BC > 2AM
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Answered by
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Answer:
So, in the triangle ABC. We have sub triangles ABM and AMC. Using the inequality of the triangle that the sum of any two sides is always greater than or equal to the third side. Hence AB+BC+CA>2AM is proved to be true
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