AM is a median of ABC. Provec that AB + BC+ CA > 2 AM
Answers
Answered by
0
Step-by-step explanation:
As we know that the sum of lengths of any two sides should be greater than the length of third side.
therefore,
In ∆ ABM
AB + BM > AM .......... ( i )
In ∆ AMC
AC + MC > AM ............. ( ii )
Adding equ. ( i ) & ( ii ) we have,
( AB + BM ) + ( AC + MC ) > AM + AM
= AB + ( BM + MC ) + AC > 2 AM
= AB + BC + AC > 2 AM
HENCE PROVED
Attachments:
Similar questions