Math, asked by ashasanghvi9672, 6 months ago

AM is a median of triangle ABC prove that AB+BC+CA>2 AM

Answers

Answered by sainisuccess

2

Answer:

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Answered by Anonymous

3

Answer:

IF AM IS MEDIAN THEN BM =MC

THEN

IN TRIANGLE ABM

AB+BM>AM. EQ1

IN TRIANGLE ACM

BC+CM>AM. EQ2.

ADD EQ1 AND EQ2

RESULTANT. =>. AB+BM+BC+CM>2AM

HENCE AB +BC+CA>2AM. (BM+CM=BC)

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