Math, asked by jishanmansoori9379, 10 months ago

AM of first n natural numbers

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Answered by Rohitsingh9982
0

Here Is your Answer-

Step-by-step explanation:

Let S be the required sum.

Let S be the required sum. Therefore, S=1+2+3+4+5+.........+n

Let S be the required sum. Therefore, S=1+2+3+4+5+.........+nClearly, it is an Arithmetic Progression whose first term = 1, last term = n and number of terms = n.

Let S be the required sum. Therefore, S=1+2+3+4+5+.........+nClearly, it is an Arithmetic Progression whose first term = 1, last term = n and number of terms = n.Therefore, S = n/2 (n + 1),

Let S be the required sum. Therefore, S=1+2+3+4+5+.........+nClearly, it is an Arithmetic Progression whose first term = 1, last term = n and number of terms = n.Therefore, S = n/2 (n + 1), [Using the formula S = n/2(a + l)]

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