Question

amahdnekakq
$find the 18th term of a.p \sqrt{2} \sqrt{18} \sqrt{50} \sqrt{98}$
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Answer 1

Answer:

35√2

Step-by-step explanation:

the 1st term (a) = √2

2nd term = √18

so, the common difference (d) = √18 - √2 = 3√2 - √2 = 2√2

the tⁿ = a + (n - 1)d

         = √2 + (18 - 1) x 2√2 = √2 + 34√2 = 35√2