Math, asked by akashtomar10005, 9 months ago

Aman Age is three times as his son's age Ten year ago he was Five times his son's age find the present ages​

Answers

Answered by Anonymous
36

Solution

Given :-

  • Aman Age is three times as his son's age
  • Ten year ago he was Five times his son's age

Find :-

  • Present age of Aman & his son's

Explanation

Let,

  • Age of Aman = x years
  • Age of his son's = y years

A/C to question,

(Aman Age is three times as his son's age)

==> x = 3y

==> x - 3y = 0-----------(1)

Again,

(Ten year ago he was Five times his son's age)

==> (x - 10) = 5 × (y - 10)

==> x - 5y = -50 + 10

==> x - 5y = -40 ----------(2)

Subtract equ(1) & equ(2)

==> -3y + 5y = 40

==> 2y = 40

==> y = 40/2

==> y = 20

Keep Value of y in equ(1)

==> x - 3 × 20 = 0

==> x = 60

Hence

  • Present Age of Aman will be (x) = 60 years
  • Present Age of his son's (y) = 20years

_________________

Answered by michaelgimmy
21

Hello, Good Morning....

Aman's age is three times as his Son's age. Ten years ago, he was five times his Son's age. Find their present ages​..

Answer:

Let Aman's Son's present age be 'x years.

Aman's age = 3x

Aman's age 10 years ago = (x - 10) years.

Aman's age 10 years ago = (3x - 10) years.

Solution:

= 3x - 10 = 5 (x - 10)

= 3x - 10 = 5x - 50

= (-10) + 50 = 5x - 3x

= 40 = 2x

Therefore, x = 20 years.

Conclusion:

Aman's Son's present age is 20 years.

Aman's age is 3x = 3 * 20 = 60 years.

(An Extract from Class 8 - Mathematics - Linear Equations In One Variable)

Hope this Helps....

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