Math, asked by ManasDheer, 1 year ago

Aman's age is three times his son's age. Ten years ago he was five times his son's age. Find their present ages.​

Answers

Answered by komalbhambri2004
10

Answer: son's age=20 years

aman's age =60 years

Step-by-step explanation:

let the son's present age be x

aman's present age=3x

ten years ago,

son's age= x-10

aman's age= 3x-10

ATQ,

3x-10=5(x-10)

3x-10=5x-50

-2x= -40

x=20

aman's age= 3x=3*20=60


komalbhambri2004: plz mark it as brainliest
Answered by ItzMahira
1

Answer:

Aman is 45 years old and his son is 15 years old.

Step-by-step explanation:

Given :

Aman's age = three times his son's age

Tens years ago = he was five times his son's age

To find :

Their present Ages

Solution :

Let the Present Ages be -

Son as x

Aman as 3x

Ages 10 Years back =

Son as (x - 10)

Aman as (3x - 10)

According to the Question -

Ten years ago he was five times his son's age

➠ (3x - 10) = 5(x - 10)

➠ 3x - 10 = 5x - 50

➠ 3x - 5x = - 50 + 10

➠ - 2x = - 30

➠ x = 30/2

➠ x = 15

Son is Presently = 15 years old

Aman's age =

➠ 3x

➠ 3(15)

➠ 45

Aman = 45 years

∴ Aman is 45 years old and his son is 15 years old.

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