Math, asked by tanujakallakkanavar, 1 year ago

Aman's age is three times times his son's age. Ten years ago he was five times his son's age. Find their present ages.

Answers

Answered by shruti1875
1

Answer:

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Step-by-step explanation:

let  \: the \: age \: of \: aman \: and \: his \: son \: be \: x \: and \: y \\x = 3y \: and  \\  x - 10 = 5(y - 10) \\  x - 10 = 5y - 50 \\ x - 5y =  - 40........(b) \\  \: substituting \: x = 3y \: in \: (b) \\ 3y - 5y =  - 40 \\  - 2y =  - 40 \\ 2y = 40 \\ y = 20 \\ x = 3y = 3 \times 20 = 60

Answered by kajal1712
6

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Let the Present age of,

His son = x

Aman = 3x

Before ten years,

His son = x - 10

Aman = 3x - 10

According to the question,Before ten years he was five time his son's age

3x - 10 = 5(x - 10)

3x - 10 = 5x - 50

3x - 5x = -50 + 10

-2x = -40

x = -40/-2

x = 20

Answer:

His son's age = 20 years

Aman's age = 3×20 = 60 years

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