Question

Amanda age is three times his son age ten years ago he was five times his son age finally their presents ages

Answer 1

Answer:

Step-by-step explanation:

Let the age of amanda be x years and his sons age be y years

Hence x= 3y--(1)and

Before 10 years ,

X-10=5(y-10)

X=5y-50+10

X=5y-40----(2)

Putting (1) in (2)

3y=5y-40

3y-5y=(-40)

-2y=(-40)

Y=(-40)÷(-2)

Y= 20

And x=3y then x= 3×20=50

Answer 2

Let Amanda 's age be x

Let Amanda 's age be xThen the son's age is y

According to the question,

>> x = 3y ( eq.01)

Now before 10yrs both becomes x - 10 yrs and y - 10 yrs.

>> x - 10 = 5(y - 10)

=> x - 10 = 5y - 50

=> x - 5y = - 50 + 10

=> x - 5y + 40 = 0 (eq.02)

Now we shall solve both the equations by substitution method ,

$x = 3y \: from \: eq.01 \\ \\ now \: we \: will \: put \: this \: value \: in \: \\ eq.02 \\ \\ \implies 3y - 5y = - 40 \\ \\ \implies - 2y = - 40 \\ \\ \implies \boxed{y = 20} \\ \\ now \: x = 3y \\ \\ \implies \boxed{x = 60}$

Hence, the age of son is 20yrs and that of father is 60yrs.