Question

If one mole of CO(g) is oxidised to CO2(g) in presence of oxygen then the difference of heat change at constant pressure and heat change at constant volume will be

Answer 1

Answer:

Change in heat for reaction = 140 kJ

Explanation:

Equation governing the oxidation reaction is:

2CO + O₂   →   2 CO₂ - 560 kJ

where 560 kJ is the enthalpy change for the oxidation reaction of CO, negative sign indicating endothermic reaction that absorbs heat from the environment during reaction time.

When 2 moles of CO undergoes oxidation according to the above reaction.

In our case, 1 mole of CO is oxidized,

Number of moles of CO oxidized are = 14/28 = 0.5 moles

Therefore, change in enthalpy for 0.5 moles of CO reaction is,

0.5 moles of CO x 560 / 2 moles of CO = 560/4 = 140 kJ