English, asked by reddygarivamsi, 5 months ago

Amar alone can complete 12.5% of a work in 2days and Raghu alone can complete the whole work in 16 days . if both work together.in how many days can they complete the whole work​

Answers

Answered by Anonymous
0

QUESTION :-

Amar alone can complete 12.5% of a work in 2days and Raghu alone can complete the whole work in 16 days . if both work together.in how many days can they complete the whole work

ANSWER :-

A’s 1 day work= 16

1 units

B’s 1 day work= 12

1 units

⇒ As they are working on alternate day's

So their 2 days work=( 161 )+( 121 )

= 48

7 units

[here is a small technique, Total work done will be 1, right, then multiply numerator till denominator, as 7×6=42,7×7=49,as7×7 is more than 48, so we will consider 7×6, means 6 pairs ]

Work done in 6 pairs=6×( 487 )= 8

42 units=12days

Remaining work=1− 8

7 = 8

On 13th day it will A turn,

16

1 work done by A in 1 day

then remaining work=( 81 )−( 161 )= 16

On 14th day it is B turn,

12

work done by B in 1 day

work will be done in (12× 161 )= 43

day

∴ total days=12+1+

43

=13

4/3 days

Please Mark branilest Answer...❤

Answered by pranavgeniusmind
0

Answer:

ANSWER

Solution

A’s 1 day work=

16

1

units

B’s 1 day work=

12

1

units

⇒ As they are working on alternate day's

So their 2 days work=(

16

1

)+(

12

1

)=

48

7

units

[here is a small technique, Total work done will be 1, right, then multiply numerator till denominator, as 7×6=42,7×7=49,as7×7 is more than 48, so we will consider 7×6, means 6 pairs ]

Work done in 6 pairs=6×(

48

7

)=

8

42

units=12days

Remaining work=1−

8

7

=

8

1

On 13th day it will A turn,

16

1

work done by A in 1 day

then remaining work=(

8

1

)−(

16

1

)=

16

1

On 14th day it is B turn,

12

1

work done by B in 1 day

16

1

work will be done in (12×

16

1

)=

4

3

day

∴ total days=12+1+

4

3

=13

4

3

days

Hence, the correct answer is none of these

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