Math, asked by hridutt6008, 17 hours ago

Amar had deposited ₹ 12000 in his saving account. He invested a part of it at 8% simple interest p.a. for 3 years and the remaining at 9% simple interest p.a. for 5 years. If the total interest earned is ₹4644, find the amount invested in each part.​

Answers

Answered by udgirkar67
0

please mark my answer as brainiests i will also mark you as brainiests

Answer:

₹20000

Step-by-step explanation:

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Peter invested an amount of Rs. 12,000 at the rate of 10 % p.a. simple interest and. another amount at the rate of 20 % p.a. simple interest. The total interest earned at the end of one year on the total amount invested became 14 % p.a. Find the total amount invested.

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Solution

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Correct option is A)

Let the second amount =x

100

12000×10×1

+

100

x×20×1

=

100

(12000+x)×14×1

100

120000

+

100

20x

=

100

168000+14x

⇒120000+20x=168000+14x

⇒20x−14x=168000−120000

⇒6x=48000

⇒x=8000

Hence total amount invested=12000+8000=20000Rs.

Answered by vdsk183
2

Answer:

ans is 3600 and 8400

Step-by-step explanation:

SI=PTR/100

x is 3600 and 12000-x is 8400

I hope this ans helps you. if yes mark me as brainliest.

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