Question

The average of the present ages of Shaun and Michal together is 8 years less than the average of the present ages of Michal and Mark together. What is the present age of Michal if the present age of Shaun, Michal and Mark are (x + 4) years, (2x + 9) years and (3x + 7) years, respectively? ​

Answer 1

Answer:

I got an answer as 28. verify if you have options.

Answer 2

Answer:

The present age of Michal is  $(2x+9)=(2*9.5+9)=28$ years.

Step-by-step Explanation:

Step-1:

The average of two numbers is $\frac{x+y}{2}$.

We are given the present ages of Shaun, Michal, and Mark $=(x+4), (2x+9), (3x+7)$ respectively.

Given, The average of present ages of Shaun and Michal is $8$ years less than the average of present ages of Michal and Mark.

$\frac{(x+4)+(2x+9)}{2}=\frac{(2x+9)+(3x+7)}{2}-8$

$x+4=3x+7-16\\x=9.5$

Hence, the present age of Michal is $(2x+9)=(2*9.5+9)=28$ years.

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