Amaravati Express after travelling 125 km met with an accident due to which it proceeds at 75% of it's original speed and arrived at its destination 35 minutes late. Had the accident took place 30 km further, then the train would have been 25 minutes late. Amaravati Express passes a pole with its original speed in 45 seconds and crosses Lucknow Express which is 20% more longer than Amaravati Express, coming in opposite direction in 0.9 minutes. Find the time taken by Lucknow Express to cover the total distance travelled by Amaravati Express
A. 4.2 hours
B. 4.4 hours
C. 4.6 hours
D. 4.8 hours
E. None of these
Answers
4.6 hrs is the time taken by Lucknow Express to cover the total distance travelled by Amaravati Express
Step-by-step explanation:
Let say Total distance = D km
Amravati original Speed = A km/hr
Original Time = D/A
Time taken for 125 km =125/A hr
Reduced Speed = (75/100)A = 3A/4 km/Hr
Time Taken = (D - 125)/(3A/4) = (4D - 500)/3A hr
125/A + (4D - 500)/3A = D/A + 35/60
=> 7500 + 80D - 10000 = 60D + 35A
=> 20D = 35A + 2500
=> 4D = 7A + 500
Had the accident took place 30 km further train would have been 25 minutes late.
=> 155/A + 4(D - 155)/3A = D/A + 25/60
=> 9300 + 80D - 12400 = 60D + 25A
=> 20D = 25A + 3100
=> 4D = 5A + 620
7A + 500 = 5A + 620
=> 2A = 120
=> A = 60
Amravati original Speed = 60 km/Hr
4D = 7A + 500
=> 4D = 920
=> D = 230
Distance = 230 km
Amaravati Express passes a pole with its original speed in 45 seconds
Distance covered in 45 sec = 60 * 45/3600 = 0.75 km = 750 m
Length of Amaravati Express Train = 750m = 0.75 km
Lucknow Express which is 20% more longer = 750 + (20/100)750 = 900 m
= 0.9 km
0.75 + 0.9 = 1.65 km
Time = 0.9 mins = 9/600 hrs
Speed = 1.65/ (9/600) = 110 km/hr
Speed of lucknow Express = 110 - 60 = 50 km/hr
the time taken by Lucknow Express to cover the total distance travelled by Amaravati Express = 230 / 50
= 23/ 5 hrs
= 4.6 Hrs
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