Question

Amir rides his bike at the speed of 28 kmph in east for 3 hours and then at the speed of 35 kmph in
west for 5 hours. Find the distance between his final position and initial position.​

Answer 1

Answer:

11.664 km

Step-by-step explanation:

See figure alongside

For 28 kmph,                                                                 9.33 km

speed= distence/time                                        A ----------------------- B

distance= speed/time= 28/3= 9.33 km                                           |

                                                                                                          |     7 km

For 35 kmph,                                                                                     |

speed= distence/time                                                                      C

distance= speed/time= 35/5= 7 km

Distance between his final position and initial position.

= AC

=$\sqrt{7^{2} + 9.33^{2} }$

=$\sqrt{49 + 87.0489}$

=11.664 km