Question

Amira takes 9 hours 25 minutes to complete a long wall

(1) Show that the time of 9 hours 25 minutes can be written as 113/12 hours.

(i) She walls (3y + 2) kilometres at 3 km/h and then a further (y+ 4) kilometres at 2 km/h

Show that the total time taken is
9y+16/6 hours.

(ül) Solve the equation 9y+16/6=113/12.

(iv) Calculate Amira's average speed, in kilometres per hour, for the whole walk.

if any of can answer that would be really good please help me. ​

Answer 1

Answer:

x= mc2 Is the formula of the given question

Answer 2

(1) 9 Hours And 25 Minutes = 113/12 Hours.

(2) Total Time Taken Is 9y+16/6 Hours.

(3)The Value Of y = 4.5

(4) The Average Speed Of Amara For The Whole Distance Is 2.54km/Hr.

GIVEN

(I) Time taken by Amara to complete a long walk- 9 hours and 25 minutes.

(2) Distance traveled - (3y +2) km

speed = 3 3rdkm/hr.

Distance traveled = (y + 4 ) km

Speed = 2 km/hr.

(3) Equation: 9y + 16/6 = 113/12

TO FIND

(1) To show 9 hours and 25 minutes can be written as 113/12 hours.

(2) To show that the total time taken is

9y+16/6 hours.

(3) solve the given equation.

(4) Average speed of Amara.

SOLUTION

We can simply solve the above problem as follows-

(1) To Show 9 Hours And 25 Minutes Can Be Written As 113/12 Hours.

Time taken by Amara = 9hour and 25 minutes.

We know that,

60 minutes = 1 hour

$1 \: minute \: = \frac{1}{60} hr$

$25 minutes = \frac{25}{60} hrs$

Simplifying,

5/12 hours

So total time taken in hours

$= 9 + \frac{5}{12}$

This can be written as -

=

$\frac{108 + 5}{12} = \frac{113}{12}hrs$

Hence, 9 hours and 25 minutes can be written as 113/12 hours.

(2) To Show That The Total Time Taken Is

To Show That The Total Time Taken Is9y+16/6 Hours.

It is given,

Distance, d1 = (3y+2) km

Speed = 3 km/hr.

Let the time taken be t1

To calculate the time taken we will apply the following formula -

$speed = \frac{distance}{time}$

$3 = \frac{3y + 2}{t1}$

So,

$t1 = \frac{3y + 2}{3} hrs$

Similarly,

Let the time taken to cover d2 distance (y+4)km with a speed of 2 km/ hr be t2.

So,

$t2 = \frac{y + 4}{2} hrs$

Total time taken = t1 + t2

=

$\frac{3y + 2}{3} + \frac{y + 4}{2}$

Since the denominators are not equal, we will take out the LCM of 2 and 3

LCM of 3 and 2 = 6

$\frac{2 \times (3y + 2)}{6} + \frac{3 \times (y + 4)}{6}$

=

$\frac{6y + 4}{6} + \frac{3y + 12}{6}$

=

$\frac{9y + 16}{6}$

Hence, the total time taken is 9y+16/6 hours.

(3)

We are given an algebraic expression -

$\frac{9y + 16}{6} = \frac{113}{12}$

Cross multiplying the denominator and numerator, we get-

$12(9y + 16) = 6 \times 113$

108y + 192 = 678

108y = 678-192

108y = 486

$y = \frac{486}{108} = 4.5$

Hence, the value of y = 4.5

(4) AVERAGE SPEED OF AMARA.

Total distance traveled = d1 + d2

Where,

d1 = (3y + 2)km

putting the value of y=4.5, we get

d1 = 3×4.5 + 2 = 15.5 km

d2 = (y + 4)km

putting the value of y=4.5, we get

d2 = 4.5+4 = 8.5 km

We can calculate the average speed by applying the following formula-

$average \: speed = \frac{total \: distance \: }{total \: time \: taken \: }$

Where,

Total distance = 15.5 + 8.5 = 24 km

Total time = 113/12 hrs.

Putting the values in the above formula, we get -

$average \: speed \: = \frac{24}{ \frac{113}{12} }$

$= \frac{24 \times 12}{113}$

288/113

= 2.54 km/hr.

Hence, the average speed of Amara for the whole distance is 2.54km/hr.

#Spj2

For more such questions-

https://brainly.in/question/47036811?utm_source=android&utm_medium=share&utm_campaign=question

https://brainly.in/question/1230645?utm_source=android&utm_medium=share&utm_campaign=question