Amit walked 16 metres South from his house turns east to walk 63 m to reach his friends house while returning he walked diagonally from his friends house to reach back to his house what distance did he walk while returning
Answers
Answered by
10
while returning home he walked 65 m
aditya149:
solve in full answer
Answered by
25
Distance covered in south=16m
Distance covered in east = 63m
Then he moved diagonally to return back home.
(If you will mame the figure you will see that it is a right angle triangle)
So using PGT
(H)^2=(P)^2 + (B)^2
(63)^2 = (P)^2 + (16)^2
P^2 = 3969 - 256
P^2 =3713
P= 60.93
Distance covered in east = 63m
Then he moved diagonally to return back home.
(If you will mame the figure you will see that it is a right angle triangle)
So using PGT
(H)^2=(P)^2 + (B)^2
(63)^2 = (P)^2 + (16)^2
P^2 = 3969 - 256
P^2 =3713
P= 60.93
Similar questions