Question

Amit walks 16m south from his house and turns East to walk 63m to reach his friend's house to reach back to his house.what distance did he walk while returning

Answer 1

Answer:he walks 65 more to reach is

House

Explanation

If he walks 16m South.

Then 63m East

If you make diagram it forms a tight angle join A to C

It look like right angled triangle

Apply Pythagoras the Rom

AC^2=16^2+63^2

AC^2= 256+3969

AC=Under root 4225

AC=65

Answer 2

Answer:

Distance covered in south=16m

Distance covered in east = 63m

Then he moved diagonally to return back home.

(If you will mame the figure you will see that it is a right angle triangle)

So using PGT

(H)^2=(P)^2 + (B)^2

(63)^2 = (P)^2 + (16)^2

P^2 = 3969 - 256

P^2 =3713

P= 60.93

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Step-by-step explanation: