Question

Amit weighing 60kgf climbs up a ladder of height 10m in 15 minutes. Calculate the increase in his potential energy and the power spent by him. (Take 1 kgf = 10 N)

Answer 1

The increase in P. E is 6000 J and the power spent by him is 400 watt.

Explanation:

Mass of the man, m = 60 kg

Height, h = 10 m

Time, t = 15 minute

We need to find the power of the man.

It is given by :

P= W / t

W = mg

P = mgh / t

P =  60 x 10 x 10 / 15

P = 400 watt

Increase in P.E = m x g x h

P . E =  60 x 10 x 10 = 6000 J

Thus the increase in P. E is 6000 J and the power spent by him is 400 watt.

Also learn more

A person carrying 10 bricks each of mass 2.5 kg on his head moves to a height 20 m in 50 seconds . Calculate the power spent in carrying bricks of the person. (g = 10 m/s 2) ?

https://brainly.in/question/288976

Answer 2

$\huge{\underline{\underline{\red{\mathfrak{AnSwEr :}}}}}$

Given :

• Mass (m) = 60 kgf = 600/10 = 60 kg
• Height (h) = 10 m
• Time (t) = 15 mins = 900 s

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To Find :

• Power
• Kinetic Energy

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Solution :

We have formula for Work Done :

$\large {\boxed{\sf{Work \: = \: mgh}}} \\ \\ \implies {\sf{Work \: = \: 60 \: \times \: 10 \: \times \: 10}} \\ \\ \implies {\sf{Work \: = \: 6000}} \\ \\ \implies {\sf{P.E \: = \: Work \: = \: 6000 \: J}} \\ \\ {\underline{\sf{\therefore \: Potential \: Energy \: is \: 6000 \: J}}}$

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Now, formula for Power is :

$\large {\boxed{\sf{Power \: = \: \dfrac{Work}{Time}}}} \\ \\ \implies {\sf{Power \: = \: \dfrac{6000}{900}}} \\ \\ \implies {\sf{Power \: = \: 6.667}} \\ \\ {\underline{\sf{\therefore \: Power \: is \: 6.67 \: W}}}$