Amit went to the market to buy some Diwali gifts for his family members. He had some Rs 10 coins, some Rs 100 notes and some Rs 500 notes in his wallet.The number of Rs 100 notes is three times the number of Rs
10coins. Also, the number of Rs 500 notes is fivemore than the number of Rs 100 notes. The total amount paid by Amit is Rs 11550, which is the exact amount he had in his wallet.Findthe number of Rs 10coinshe had in his wallet.
Answers
Answer
No. of 100 rupee notes = 3 × 10 coins
No. of 500 rupee notes = 5 × 100 notes
Total amount paid by Amit = 11,550rs
Total amount in the wallet = 11550+(3×10)+(5×100)
11550+530
12080
therefore, remaining amount in wallet= 12080 - 11550
= 530 rs
Given: Amit went to the market to buy some Diwali gifts for his family members. He had some Rs 10 coins, some Rs 100 notes and some Rs 500 notes in his wallet. The number of Rs 100 notes is three times the number of Rs 10 coins. Also, the number of Rs 500 notes is fivemore than the number of Rs 100 notes. The total amount paid by Amit is Rs 11550, which is the exact amount he had in his wallet.
To find: Number of Rs 10 coins in his wallet
Solution: Let the number of Rs 10 coins be x, number of Rs 100 notes be y and number of Rs 500 notes be z.
Number of Rs 100 notes is three times the number of Rs 10 coins.
y=3x -----equation (i)
The number of Rs 500 notes is five more than the number of Rs 100 notes.
z=y+5
Using y=3x in this equation:
z=3x+5
z -3x - 5 =0 ------equation(ii)
The total amount in his wallet
= Rs 10 × x + Rs 100 × y + Rs 500 × z
= 10x+100y+500z
But total amount is given as 11550.
Therefore,
10x+100y+500z= 11550
Using y= 3x in this equation:
10x+300x+500z=11550
=> 310x+500z= 11550
=> 31x+50z= 1155
Multiplying equation (ii) by -50 and adding equation (iii):
-50(z-3x-5)+ 31x+50z=0+1155
=> -50z+150x+250+31x+50z= 1155
=>181x+250 = 1155
=> 181x = 1155-250
=> 181x = 905
=> x = 905/181
=> x = 5
Therefore, the number of Rs 10 coins is 5.