Question

Ammonia gas and hydrogen chloride gas Combine
to make ammonium chloride what volume of
ammonia at STP is needed to dealt with 4 7.7
litres of hydrogen chloride at STP?​

Answer 1

ANSWER

(i) 1 mole occupies 22.4L volume

∴ moles of NH  

3

​  

 present=  

22.4

67.2

​  

=3

(ii) 1 mole of NH  

3

​  

 reacts with 1 mole of HCl to give 1 mole of NH  

4

​  

Cl. Here only 1 mole of HCl & 3 moles of NH  

3

​  

 are present. Hence, 1 mole of NH  

4

​  

Cl is produced.

Mass of NH  

4

​  

Cl produced= 1× Molecular mass

                                             =1×(14+4×1+35.5)

                                             =53.5g

(iii) Here NH  

3

​  

 is present in excess than what is required to react with 1 mole HCl. Hence 3−1=2 moles of NH  

3

​  

 will remain after completion of the reaction.

(iv) Chemical reaction involved is:

NH  

3

​  

+HCl⟶NH  

4

​  

Cl .