Ammonia gas diffuses twice as fast as gas x. The gas X is
A) SO2
B)C4H10
C)C5H8
D)Cl2
Answers
Answered by
14
HII✨✔✔
HERE IS YOUR ANSWER ☺☺
RATE IS INVERSELY PROPORTIONAL TO SQUARE ROOT OF MOLECULAR MASS .
SO THE ANSWER IS OPTION C
HERE IS YOUR ANSWER ☺☺
RATE IS INVERSELY PROPORTIONAL TO SQUARE ROOT OF MOLECULAR MASS .
SO THE ANSWER IS OPTION C
Answered by
28
According to the Graham's Law of Diffusion,
Rate is inversely proportional to the square root of the molecular mass of the compound
So,
R1/R2 = √M2/M1
Thus, the rate of NH3 to be double the molecular mass of the compound X should be 4 times the molar mass of Ammonia.
Molar mass of NH3 = 17
Thus, Molar mass of Gas X should be 17*4 = 68.
And we know that the molar mass of C5H8 is 68 ( 5*Mass of carbon + 8* Hydrogen = 5*12+8*1 = 68)
Hence, the answer should be C) C5H8.
Rate is inversely proportional to the square root of the molecular mass of the compound
So,
R1/R2 = √M2/M1
Thus, the rate of NH3 to be double the molecular mass of the compound X should be 4 times the molar mass of Ammonia.
Molar mass of NH3 = 17
Thus, Molar mass of Gas X should be 17*4 = 68.
And we know that the molar mass of C5H8 is 68 ( 5*Mass of carbon + 8* Hydrogen = 5*12+8*1 = 68)
Hence, the answer should be C) C5H8.
keerthisree7:
nice explanation
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