Ammonium carbamate decomposes as
NH2COONH4(s) gives2NH3(g) + CO2(g)
For this reaction, Kp = 108 x 10-6 atm? If we start
with 1 mole of the compound, the total pressure at
equilibrium would be
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Answer:
Answer
NH
2
COONH
4
(s)⇌2NH
3
(g)+CO
2
(g)
(p
NH
3
)=2x
(p
CO
2
)=x
K
p
=(p
NH
3
)
2
×p
CO
2
2.9×10
−5
=(2x)
2
×x=4x
3
x=(
4
2.9×10
−5
)
1/3
=0.0194atm
Total pressure =2x+x=3x=3×0.0194=0.058 atm
may this help u!!!!
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