Question

ammonium carbamate dissociates as NH2COONH4 in a closed vessel containing ammonium carbamate in equilibrium ammonia is added such that the partial pressure of NH3 now equals to the original total pressure the ratio of total pressure now to the original pressure is ​

Answer 1

Answer:

The formula is

$NH_{2} COONH_{4} (s)$⇄$2NH_{3} (g)+CO_{2} (g)$

initial

$K_{p} =(pNH_{3} )^{2} (pCO_{2} )$

$K_{p} =(2P)^{2} (P)-------(i)$

considering the second case

$K_{p} =(3P)^{2} (P^{'} )---------(ii)$

From equation (i) and (ii) we get

$(2P)^{2} (P)=(3P)^{2} (P^{'} )$

$P^{'} =\frac{4P}{9}$

$\frac{P_{T}(new) }{P_{T}(old) } =\frac{3P+P^{'} }{3P}$

=$\frac{3P+\frac{4P}{9} }{3P}$

=$\frac{31}{27}$

Answer 2

Anwer:⬇️⬇️⬇️⬇️

▶️31/27◀️