Math, asked by sumita78901, 2 months ago

Among how many people can 27 copies, 45 pencils and
63 pens be divided, at most? How many copies, pencil
and pen everyone get?
with statement​

Answers

Answered by Swarup1998
3

Given data :

Number of copies = 27

Number of pencils = 45

Number of pens = 63

To find :

Number of people

Number of each item that everyone will get

Step-by-step explanation :

First we find the gcd of 27, 45 and 63

Here, 27 = 3 × 3 × 3

45 = 3 × 3 × 5

63 = 3 × 3 × 7

Thus, gcd (27, 45, 63) = 3 × 3 = 9

Hence among 9 people those items be divided at most.

Each will get (27 ÷ 9) = 3 copies, (45 ÷ 9) = 5 pencils and (63 ÷ 9) = 7 pens.

Answers :

Among 9 people, 27 copies, 45 pencils and 63 pens can be divided, at most. Everyone will get 3 copies, 5 pencils and 7 pens.

Answered by HorridAshu
17

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Given data :

Number of copies = 27

Number of pencils = 45

Number of pens = 63

To find :

Number of people

Number of each item that everyone will get

Step-by-step explanation :

First we find the gcd of 27, 45 and 63

Here, 27 = 3 × 3 × 3

45 = 3 × 3 × 5

63 = 3 × 3 × 7

Thus, gcd (27, 45, 63) = 3 × 3 = 9

Hence among 9 people those items be divided at most.

Each will get (27 ÷ 9) = 3 copies, (45 ÷ 9) = 5 pencils and (63 ÷ 9) = 7 pens.

Answers :

Among 9 people, 27 copies, 45 pencils and 63 pens can be divided, at most. Everyone will get 3 copies, 5 pencils and 7 pens.

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