Question

among I,I- AND I+ which is having least and largest radii?Arrange them in increasing order of their radii

Answer 1

Answer:

I- is largest and I+ is smallest ion .

I- > I > I+

Explanation:

when the number of electrons are same size of MONO atomic ion increases as the number of electrons increases.

More electrons means more repulsion between electrons and hence bigger size.

Answer 2

Given species are arranged in increasing order of their radii as follows.

              $I^{+}$ < I < $I^{-}$

Explanation:

More is the number of electrons present in an atom more will be its atomic radii. When an atom gain electrons then it acquires a negative charge and when an atom acquires a positive charge then it means the atom has lost electrons.

Atomic number of iodine (I) is 53 and its electronic configuration is $[Kr]4d^{10}5s^{2}5p^{5}$.

Number of electrons present in $I^{-}$ is 54 and its electronic configuration is $[Kr]4d^{10}5s^{2}5p^{6}$.

Number of electrons present in $I^{+}$ is 52 and its electronic configuration is $[Kr]4d^{10}5s^{2}5p^{4}$.

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