Question

calculate the energy of electron in 1st orbit of hydrogen atom

Answer 1

The total energy of an electron in the first Bohr orbit of hydrogen atom is -13.6eV. So the Potentital energy of an electron in the first Bohr orbit of hydrogen atom=2*(-13.6) eV= -27.2evIn atomic , molecular and solid state physics, system of atomic units is used

Answer 2

Answer: -2.18×10^-18 J or -13.6 ev

Explanation:n=1

E= - RH ( Z²)/( n²)

= -RH (1²)/(1²)

E=-RH. Here H= plenck's constant

E= -2.18×10^-18 J or -13.6 ev