Chemistry, asked by fahminfayasakpcx4ke, 1 year ago

among N ^3- ,O ^2- ,F ^-1, Na^+ and Al^3+, which one has the smallest size? why?

fahminfayasakpcx4ke: *2*- AL3+

these ions have 10 electrons in their shell therefore these areisoelectronic speicies
The more + the charge, the smaller the ionic radius. Remember that - means adding electrons. These electrons go in the outermost shells. Also, when an atom loses electrons, it clings ever more tightly to the ones it has left, further reducing the ionic radius. therefore the order of ionic radii will be →

AL3+< Na+< F-

Answers

Answered by Anonymous

hey buddy... !! here's your answer....

➡️the smallest size is of Al 3+ because it has lost 3 electrons... but nucleus still has same no. of protons ... so they will attract electrons more efficiently than before ...

hope it helps ❤️✌️

Answered by Anonymous

Al3+ < Mg2+ < Na+ < F– < O2– < N3–
thus the smallwst sinze is...ofAl3...
becoz....The ionic radii of isoelectronic species increases with a decrease in the magnitudes of nuclear charge....if not cleared...comment...i will be happy to explain...

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