Among NH3,HNO3, NaN3 and Mg3N2 the no of molecules having nitrogen in negative oxidation state is
Answers
Answered by
0
Explanation:
The oxidation number of N in NH
3
,NH
2
OH,NaN
3
and NH
4
NO
2
are −3,−1,−
3
1
,+3/−3 respectively.
Let X be the oxidation number of N in NH
3
.
X+3=0
X=−3
Let X be the oxidation number of N in NH
2
OH.
X+3−2=0
X=−1
Let X be the oxidation number of N in NaN
3
.
1+3X=0
X=
3
−1
Oxidation state of N in NH
4
NO
2
,
The given molecule is made up of the combination of two ions which are ammonium ion (NH
4
+
) and nitrate ion (NO
2
−
). In this, nitrate ion is the counter ion.
Now we have to determine the oxidation number of N in both the ions.
The oxidation number of N in NH
4
+
:
X+4=1
X=−3
The oxidation number of N in NO
2
−
:
X−4=−1
x=+3
Similar questions