Science, asked by Tarun8431, 10 months ago

among the elements 2He^4,7N^14,12Mg^24 and 4Be^8,the elements which belong to the same period in the modern periodic table are

A. 2He^4 and 4Be^8
B. 7N^14 and 4Be^8
C. 12Mg^24 and 2He^4
D. 4Be^8 and 12Mg^24

Answers

Answered by Ïmpøstër

Explanation:

D. 4Be^8 and 12Mg^24......

hope it helps.......☺☺☺☺

Answered by ItzUnic0rns

$<!DOCTYPE html><html><head><style>#grad1 {height: 300px;background-color: red; /* For browsers that do not support gradients */background-image: linear-gradient(to right, blue ,red,yellow,orange); /* Standard syntax (must be last) */}</style></head><body><div id="grad1" style="text-align:center;margin:auto;color:#000000;font-size:20px;font-weight:bold">Option D is correct answer </div></body></html>$

Previous Question

Next Question

among the elements 2He^4,7N^14,12Mg^24 and 4Be^8,the elements which belong to the same period in the modern periodic table areA. 2He^4 and 4Be^8 B. 7N^14 and 4Be^8C. 12Mg^24 and 2He^4D. 4Be^8 and 12Mg^24​

Answers

among the elements 2He^4,7N^14,12Mg^24 and 4Be^8,the elements which belong to the same period in the modern periodic table are

A. 2He^4 and 4Be^8
B. 7N^14 and 4Be^8
C. 12Mg^24 and 2He^4
D. 4Be^8 and 12Mg^24