Question

Among the followinf molecules the highest bond order is of F2,O2,N2,C2

Answer 1

Answer:

Taking 14 as reference point and has bond order 3 . On adding or subtracting 1 , there is decrease of 0.5 in each .

Now for F₂ :

9 × 2 = 18

It is + 4 then reference point i.e. decrease of 2.

Bond order of F₂ = 3 - 2 = >  1

For O₂ :

8 × 2 = 16

It is + 2 then reference point i.e. decrease of 1.

Bond order of O₂ = 3 - 1 = >  2

For N₂ :

7 × 2 = 14

It is + 0 then reference point i.e. decrease of none.

Bond order of N₂ = 3

For C₂ :

6 × 2 = 12

It is - 2 then reference point i.e. decrease of 1.

Bond order of O₂ = 3 - 1 = >  2 .

Now we clearly see N₂ has highest bond order i.e. B.O. 3 .