Among the following, molecules with sp3d hybridisation is
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Answer:
PCL5, XeF2,
Explanation:
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The whole question is as follows:
Among the following, molecules with sp3d hybridisation is
A) NH4+
B) SF4
C) XeF4
D) XeOF4
Answer:
The correct answer is option B) SF4.
Explanation:
For NH4+ :
- Nitrogen has 5 electrons in its outer shell.
- In which 3 electrons form 3 bonds with 3 electrons of hydrogens.
- Other 2 electrons form a bond with hydrogen ion.
- The total number of bonds is 4, so it corresponds to Sp³ hybridization.
For SF4:
- Sulphur has 6 electrons in its outer shell.
- In which 4 electrons form 4 bonds with fluorine and have 1 lone pair of electron.
- A Total of 5 bonds are there in SF4 so, it has Sp³d hybridization.
For XeF4:
- Xe has 8 electrons in its outer shell.
- In which 4 electrons form 4 bonds with fluorine and have 2 lone pairs of electron.
- A total of 6 bonds are there in XeF4 so, it has Sp³d² hybridization.
For XeOF4:
- Xe has 8 electrons in its outer shell.
- In which 4 electrons form 4 bonds with fluorine and 2 electrons form 2 bonds in which one is a pi bond with oxygen and other 2 lone pairs of electron.
- A total of 7 bonds in which one is a pi bond are there in XeOF4, it has Sp³d² hybridization.
So, from above discussion it is proved that SF4 has Sp³d hybridization.
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