Chemistry, asked by athul4, 1 year ago

Among the metal carbonyls [Mn(CO)6]

+, [Ti(CO)6], [Cr(CO)6] and [V(CO)6]

−, the C-O bond

order would be lowest in

Answers

Answered by lakshi3
2
Ti(CO)6...as. .The Ti− complex, involving the only d5 metal in a host of d6 metals, is actually the one with thesmallest bond order because it has the leastnumber of electrons in the t2g orbitals, which are always nonbonding if σ donation is present but πacceptance is not, and may be at least a bit bonding when π acceptance is additionallypresent.

The less electrons present in the t2g bondingorbitals, the less bonding character, and thus theweaker the metal-ligand interactions are.

Additionally, because it is the transition metal out of these four that has the largest ionic radius (yet uses the same set of d orbitals), its metal-ligand distance is largest, and that weakens the metal-ligand interactions a bit more.
Similar questions